# Vertices sentence examples

vertices
• This solid has 4 faces, 4 vertices and 6 edges.

• It consequently has four vertices and six edges.

• The funicular or link polygon has its vertices on the lines of action of the given forces, and its sides respectively parallel to the lines drawn from 0 in the force-diagram; in particular, the two sides meeting in any vertex are respectively parallel to the lines drawn from 0 to the ends of that side of the force-polygon which represents the corresponding force.

• be situate at the vertices of a triangle ABC, the mass-centre of ~ and y is at a point A in BC, such that ~.

• ., and of a series of lines connecting the vertices with a point 0.

• Again, if G be the mass-centre of four particles a, \$, 7, situate at the vertices of a tetrahedron ABCD, we find a: ~ :~: tet GBCD: tetUGCDA: tetGDAB: tetGABC, and by suitable determination of the ratios on the left hand we can make G assume any assigned position in space.

• be successive vertices, and let H, K...

• The truncated octahedron is formed by truncating the vertices of an octahedron so as to leave the original faces hexagons; consequently it is bounded by 8 hexagonal and 6 square faces.

• Two polyhedra are reciprocal when the faces and vertices of one correspond to the vertices and faces of the other.

• This solid has therefore 6 faces, 8 vertices and 12 edges.

• take the pole of each face of such a polyhedron with respect to a paraboloid of revolution, these poles will be the vertices of a second polyhedron whose edges are the conjugate lines of those of the former.

• and at equal horizontal intervals, the vertices of the funicular will lie on a parabola whose axis is vertical.

• Through the vertices A, B, C,..

• Cayley gave the formula E + 2D = eV + e'F, where e, E, V, F are the same as before, D is the same as Poinsot's k with the distinction that the area of a stellated face is reckoned as the sum of the triangles having their vertices at the centre of the face and standing on the sides, and e' is the ratio: " the angles subtended at the centre of a face by its sides /2rr."

• The truncated dodecahedron is formed by truncating the vertices of a dodecahedron parallel to the faces of the coaxial icosahedron so as to leave the former decagons.

• A polyhedron (A) is said to be the summital or facial holohedron of another (B) when the faces or vertices of A correspond to the edges of B, and the vertices or faces of A correspond to the vertices and faces together of B.

• In all cases the magnitude and direction, and joining the vertices of the polygon thus formed to an arbitrary pole 0.

• If we take any polyhedron with plane faces, the null-planes of its vertices with respect to a given wrench will form another polyhedron, and the edges of the latter will be conjugate (in the above sense) to those of the former.

• A connexion between the number of faces, vertices and edges of regular polyhedra was discovered by Euler, and the result, which assumes the form E + 2' = F ± V, where E, F, V are the number of edges, faces and vertices, is known as Euler's theorem on polyhedra.

• The points in which the cutting plane intersects the sides of the triangle are the vertices of the curve; and the line joining these points is a diameter which Apollonius named the latus transversum.

• 6KT6, eight, Spa, base), a solid bounded by eight triangular faces; it has 6 vertices and 12 edges.

• SX may be also divided externally at A', so that SA'/A'X = e, since e is less than unity; the points A and A' are the vertices, and the line AA' the major axis of the curve.

• The truncated tetrahedron is formed by truncating the vertices of a regular tetrahedron so as to leave the original faces hexagons.

• Denoting them by x, y, so that AB is axis of y and a perpendicular through A the axis of x, and rationalizing (26), we have 2 ax 2 - V 2 Xy 2 - V 2 aAy = o, which represents a hyperbola with vertices at 0 and A.

• The points thus obtained are evidently the vertices of a polyhedron with plane faces.

• As regards the former figure this is evident at once; viz, the polyhedron consists of two pyramids with vertices represented by 0, 0, and a common base whose perimeter is represented by the forcepolygon (only one of these is shown in fig.

• In Newton's method, two angles of constant magnitude are caused to revolve about their vertices which are fixed in position, in such a manner that the intersection of two limbs moves along a fixed straight line; then the two remaining limbs envelop a conic. Maclaurin's method, published in his Geometria organica (1719), is based on the proposition that the locus of the vertex of a triangle, the sides of which pass through three fixed points, and the base angles move along two fixed lines, is a conic section.

• rEoo-apes-KaiSEKa, fourteen) formed by truncating the vertices of a cube so as to leave the original faces squares.

• Svo - Kat- rpoieKovra, thirty-two), is a 32-faced solid, formed by truncating the vertices of an icosahedron so that the original faces become triangles.

• He discriminated the three species of conics as follows: - At one of the two vertices erect a perpendicular (talus rectum) of a certain length (which is determined below), and join the extremity of this line to the other vertex.

• For instance, considering four equal particles at the vertices of a regular tetrahedron, we can infer that the radius R of the circumscribing sphere is given by R2=j a2, if a be the length of an edge.

• Yet this number, although it represents a portentous expenditure of labour, is insignificant compared with the multitude of the stellar throng; nor had any general tendency been discerned to regulate what seemed casual flittings until Professor Kapteyn, in 1904, adverted to the prevalence among all the brighter stars of opposite streamflows towards two " vertices " situated in the Milky Way (see Star).

• Three pentagons may be placed at a common vertex to form a solid angle, and by forming several such sets and placing them in juxtaposition .a solid is obtained having 12 pentagonal faces, 30 edges, and 20 vertices.

• A volume data set is often modeled by decomposing its domain through a tetrahedral mesh with vertices at the data points.

• Drawing polygons Use the polygon tool to click points representing the vertices of the required polygon.

• The vertices of the triangles form irregularly spaced nodes.

• Shortest Path between two vertices of a graph (edges are weighted).

• One needs to select all atoms in the cage - these will be the vertices of the final polyhedron.

• The distance between adjacent vertices of the icosahedron is 5% longer than the distance between a vertex and the center.

• Every four values in the array correspond to the vertices of a single tetrahedron.

• Question 6 The table below lists the edges and their associated costs in a graph containing 8 vertices (A to H).

• We'll also be making sure all the polygons have four vertices (called quads).

• The guess solution is a list of vertices v 1, v 2, ¼, v K.

• Gomberg's triphenyl-methyl play no part in what follows), it is readily seen that the simplest hydrocarbon has the formula CH 4, named methane, in which the hydrogen atoms are of equal value, and which may be pictured as placed at the vertices of a tetrahedron, the carbon atom occupying the centre.

• More briefly, the figure may be defined as a polyhedron with two parallel faces containing all the vertices.

• As particular cases: the mass-centre of a uniform thin triangular plate coincides with that of three equal particles at the corners; and that of a uniform solid tetrahedron coincides with that of four equal particles at the vertices.

• Thus the general curve of three bar-motion (or locus of the vertex of a triangle, the other two vertices whereof move on fixed circles) is a tricircular sextic, having besides three nodes (m = 6, 6 = 3+3+3, = 9), and having the centres of the fixed circles each for a singular focus; there is a third singular focus, and we have thus the remarkable theorem (due to S.

• Of the properties of a tangent it may be noticed that the tangent at any point is equally inclined to the focal distances of that point; that the feet of the perpendiculars from the foci on any tangent always lie on the auxiliary circle, and the product of these perpendiculars is constant, and equal to the product of the distances of a focus from the two vertices.

• Then A, A' are the 1,[ N vertices of the curve.

• Two such sets placed base to base form the octahedron, which consequently has 8 faces, 6 vertices and 12 edges.

• Five equilateral triangles covertically placed would stand on a pentagonal base, and it was found that, by forming several sets of such pyramids, a solid could be obtained which had zo triangular faces, which met in pairs to form 30 edges, and in fives to form 12 vertices.

• - These solids have all their faces equal regular polygons, and the angles at the vertices all equal.

• It has 12 pentagonal faces, and 30 edges, which intersect in fives to form 12 vertices.

• It has 12 faces, which meet in 30 edges; these intersect in threes to form 20 vertices.

• Each of the twenty triangular faces subtend at the centre the same angle as is subtended by four whole and six half faces of the Platonic icosahedron; in other words, the solid is determined by the twenty planes which can be drawn through the vertices of the three faces contiguous to any face of a Platonic icosahedron.

• (By the truncation of a vertex or edge we mean the cutting away of the vertex or edge by a plane making equal angles with all the faces composing the vertex or with the two faces forming the edge.) It is bounded by 4 triangular and 4 hexagonal faces; there are 18 edges, and 12 vertices, at each of which two hexagons and one triangle are covertical.

• Two polyhedra correspond when the radii vectores from their centres to the mid-point of the edges, centre of the faces, and to the vertices, can be brought into coincidence.

• coordinates of the selected vertices is calculated.

• equal in length to the number of vertices of the plot or it will be ignored.

• Estimation of the motion for the other vertices forming the hexagon is performed in a similar manner.

• mouse button click will delete the vertices in reverse order.

• permuteallows for permuting the vertices within a class.

• Each stage of refinement defines a new, denser, polyhedron whose vertices are related to local sets of vertices of the original.

• The head of this list is iteratively decimated and the list updated until a target number of vertices for the sparse polyhedron is met.

• polyhedron with 14 vertices.

• Outline shapes Outline shapes, such as triangles, rectangles and parallelograms, consist of a series of straight-line segments between the vertices.

• tetrahedral mesh with vertices at the data points.

• vertices of the required polygon.

• vertices of the triangles form irregularly spaced nodes.

• vertices of a graph (edges are weighted ).

• vertices of the final polyhedron.

• vertices of the icosahedron is 5% longer than the distance between a vertex and the center.

• vertices of a single tetrahedron.

• These connect any two opposite vertices which do not belong to the same face.

• The region is defined by selecting vertices using a graphics cursor.

• If we delete the edge e joining the two vertices of degree 3 we get a circuit C 6.

• Question 6 The table below lists the edges and their associated costs in a graph containing 8 vertices (A to H ).

• We'll also be making sure all the polygons have four vertices (called quads ).

• Pairs of labeled vertices from these polyhedrons comprise a set of correspondences.

• The generic method actually deletes the selected vertices including all their edges.

• Using the ruler draw lines connecting the adjacent vertices of the hexagon.

• You get lots of output in the GAP command window and seven new vertices.

• How many vertices (corners) and edges are there?

• Average X Positions Selecting this entry will average the x coordinates of two or more selected vertices.

• The other vertices are then pairs of adjacent atoms running around the ring.

• vertices v 1, v 2, ¼, v K.

• This problem is composed of a graph of n vertices, linked by legal paths.

• If the perpendiculars from the vertices to the opposite faces of a tetrahedron be concurrent, then a sphere passes through the four feet of the perpendiculars, and consequently through the centre of gravity of each of the four faces, and through the mid-points of the segments of the perpendiculars between the vertices and their common point of intersection.

• This theorem has been generalized for any tetrahedron; a sphere can be drawn through the four feet of the perpendiculars, and consequently through the mid-points of the lines from the vertices to the centre of the hyperboloid having these perpendiculars as generators, and through the orthogonal projections of these points on the opposite faces.

• Thus it has a real centre, two foci, two directrices and two vertices; the transverse axis, joining the vertices, corresponds to the major axis of the ellipse, and the line through the centre and perpendicular to this axis is called the conjugate axis, and corresponds to the minor axis of the ellipse; about these axes the curve is symmetrical.

• Calling the foci S, S', the real vertices A, A', the extremities of the conjugate axis B, B' and the centre C, the positions of B, B' are given by AB = AB' = CS.

• Some properties of the curve will be briefly stated: If PN be the ordinate of the point P on the curve, AA' the vertices, X the meet of the directrix and axis and C the centre, then PN 2: AN.NA':: SX 2: AX.A'X, PN 2 is to AN.NA' in a constant ratio.

• Two such sets can be placed so that the free edges are brought into coincidence while the vertices are kept distinct.