# Perpendiculars Sentence Examples

Also the auxiliarly circle is the locus of the feet of the

**perpendiculars**from the foci on any tangent.Inside an equilateral triangle, for instance, of height h, - 2Ra/3y/h, (8) where a, 13, y are the

**perpendiculars**on the sides of the triangle.The orthogonal projection of a section of this surface by a plane containing one of the

**perpendiculars**and inclined to the axis is the quadratrix.From every point of the curve of intersection,

**perpendiculars**are drawn to the axis.The quadrilateral, for instance, consists of two triangles, and its area is the product of half the length of one diagonal by the sum of the

**perpendiculars**drawn to this diagonal from the other two angular points.AdvertisementOr generally, if M 1 M2 M3 are the moments of the external forces to the left of 0, A, and B respectively, and s, t and c the

**perpendiculars**from 0, A and B on the directions of the forces cut by the section, then Ss=M11 Tt=M2andCc=M3.Since - the side OA is common, we have o to prove that the sum of the - -

**perpendiculars**from B and C on - -.Hence also the ratio of the com ponents of the velocities of two points A and B in the directions AP and BW respectively, both in the plane of rotation, is equal to the ratio of the

**perpendiculars**Fni and Fn.Application to a Pair of TurnIng Fseces.Let ai, a2 be the angular velocities of a pair of turning pieces; Of, Oi the angles which their line of connection makes with their respective planes of rotation; Ti, r2 the common

**perpendiculars**let fall from the line of connection upon the respective axes of rotation of the pieces.The axes of rotation of a pair of turning pieces connected by a link are almost always parallel, and perpendicular to the line of connection n which case the angular velocity ratio at any instant is the recipocal of the ratio of the common

**perpendiculars**let fall from the me of connection upon the respective axes of rotation.AdvertisementBut, p and q being respectively the

**perpendiculars**to the lines of action of the forces, this equation reduces to Pp=Rq, FIG.Of the properties of a tangent it may be noticed that the tangent at any point is equally inclined to the focal distances of that point; that the feet of the

**perpendiculars**from the foci on any tangent always lie on the auxiliary circle, and the product of these**perpendiculars**is constant, and equal to the product of the distances of a focus from the two vertices.The more commonly used length measurements -- length overall, length between

**perpendiculars**, and length on load waterline are discussed as follows.If the

**perpendiculars**from the vertices to the opposite faces of a tetrahedron be concurrent, then a sphere passes through the four feet of the**perpendiculars**, and consequently through the centre of gravity of each of the four faces, and through the mid-points of the segments of the**perpendiculars**between the vertices and their common point of intersection.This theorem has been generalized for any tetrahedron; a sphere can be drawn through the four feet of the

**perpendiculars**, and consequently through the mid-points of the lines from the vertices to the centre of the hyperboloid having these**perpendiculars**as generators, and through the orthogonal projections of these points on the opposite faces.Advertisement