# Xb sentence example

xb

- X (xa) ki (xb) k2 (xc) k3...axibx2cx3...xx = (AB) hi (AC) h2 (BC) h3...A11 4 13 A1,14131 A B I ?C"' B C "' X (XA) ki (XB) k2 (XC) k3...AXB122cCk...X If this be of order e and appertain to an nie L Eke-/1+2m =e, h i+h2+ï¿½ï¿½ï¿½+221+ji+j2+ï¿½ï¿½ï¿½+kl+li =n, hi+h3+..ï¿½+222+ji+j3+ï¿½ï¿½ï¿½+k2+12 = n, h2+h3+ï¿½ï¿½ï¿½+223+j2+%3+ï¿½.ï¿½+k3+13 =n; viz., the symbols a, b, c,...
- u -b' Along a jet surface, q=Q, and ch S2= cos 0 =cos a-i sin2a(a-a')/(u-b), (5) if 0 =-a at the source x of the jet xB, where u = co; and supposing 0=0,13 at the end of the streams where u =j, j', u-b i sin 2 a u - j cos 0-cos /3 i a -a cos a sin a -cos 0' aa' - 2 (cos a -cos (3) (cos a-cos 0)' u-j' 1 2 cos 0-cos, (6) a -a' - 2 S i n a (cos a -cos (3') (cos a -cos B)' and 4' being constant along a stream line d4 - dw ds _d8 d4 _ dw du du du' d- -dud0' 7rQ ds_ it ds (cos a-cos /3) (cos a -cos (3') sin 0 m+m' dB c d0 - (cos a-cos B) (cos 0-cos /3) (cos 0 -cos /3')' _ sin 0 cos a-cos 13 sin 0 - cos a-cos B + cos 0-cos (3' cos 0-cos 13 cos a -cos $ sin 6 cos (3-cos /3' cos 0-cos 0" giving the intrinsic equation of the surface of a jet, with proper attention to the sign.
- C. Miscellaneous 1.1 Hpo/ Xb,LCara: Problemata: Problems on various subjects [gradually collected by the Peripatetics from partly Aristotelian materials, according to Zeller].
- 123 and 124) is the following: If points X and x are taken dividing the link BC and the tangential velocity cb, sothat cx: xb=CX:XB, then Ox represents the velocity of the point X in magnitude and direction.
- $ VN OFt .twkihur?h, 'etnerbu Ma ide n e ?` ll xb o, { ?y,r' ?Advertisement
- Belzebul, and in XB, Beezebul), all variants of Beelzebul.
- The XB also features a downdraft Ram Air intake that increases airflow and power at high speeds.
- X (xa) ki (xb) k2 (xc) k3...axibx2cx3...xx = (AB) hi (AC) h2 (BC) h3...A11 4 13 A1,14131 A B I ?C"' B C "' X (XA) ki (XB) k2 (XC) k3...AXB122cCk...X If this be of order e and appertain to an nie L Eke-/1+2m =e, h i+h2+Ã¯¿½Ã¯¿½Ã¯¿½+221+ji+j2+Ã¯¿½Ã¯¿½Ã¯¿½+kl+li =n, hi+h3+..Ã¯¿½+222+ji+j3+Ã¯¿½Ã¯¿½Ã¯¿½+k2+12 = n, h2+h3+Ã¯¿½Ã¯¿½Ã¯¿½+223+j2+%3+Ã¯¿½.Ã¯¿½+k3+13 =n; viz., the symbols a, b, c,...
- When the barrier AA' is held oblique to the current, the stream line xB is curved to the branch point B on AA' (fig.