The polygon of forces is then made up of segments of a vertical line.
At the joint between the pieces to which the two loads reprfsented by the contiguous sides of the polygon of loads (such as L1, L2, &c.) are applied; then will all those lines meet in one point (0), and their lengths, measured from that point to the angles of Ike polygon, will represent the magnitudes of the resistances to which they are respectively parallel.
In the polygon of loads the direction of a load sustained by parallel resistances traverses the point O-i i Since the relation discussed in 7 was enunciated by Rankine, an enormous development has taken place in the subject of Graphic Statics, the first comprehensive textbook on the subject being Die Graphische Statik by K.
Hence the necessary and sufficient conditions of equilibrium are that the force-polygon and the funicular should both be closed.
According to a well-known principle of statics, because the loads or external pressures P1L~, &c., balance each other, they must be proportional to the sides of a closed polygon drawn respectively parallel to their directions.
When all the forces are vertical, as will be the case in girders, the polygon of external forces will be reduced to two straight lines, fig.
The funicular or link polygon has its vertices on the lines of action of the given forces, and its sides respectively parallel to the lines drawn from 0 in the force-diagram; in particular, the two sides meeting in any vertex are respectively parallel to the lines drawn from 0 to the ends of that side of the force-polygon which represents the corresponding force.
Considering, in the first place, the case in which the load and the two resistances by which each piece is balanced meet in one point, which may be called the centre of load, there will be as many such points of intersection, or centres of load, as there are pieces in the structure; and the directions and positions of the resistances or mutual pressures exerted between the pieces will be represented by the sides of a polygon joining Pi h2 ~, ~ those points, as in fig.
In considering its properties, the load at each centre of load is to be held to include the resistances of those joints which are not comprehended in the partial polygon of resistances, to which the theorem of 7 will then apply in every respect.
Michell has discussed also the hollow vortex stationary inside a polygon (Phil.
If there are no redundant members in the frame there will be only two members abutting at the point of support, for these two members will be sufficient to balance the reaction, whatever its direction may be; we can therefore draw two triangles, each having as one side the reaction YX, and having the two other sides parallel to these two members; each of these triangles will represent a polygon of forces in equilibrium at the point of support.
67 a) in a fitting position to represent part of the polygon of forces at Xefa; beginning with the upward thrust EX, continuing down XA, and drawing AF parallel to AF in the frame we complete the polygon by drawing EF parallel to EF in the frame.
The latter, as we know, calculated the perimeters of successive polygons, passing from one polygon to another of double the number of sides; in a similar manner Gregory calculated the areas.
This diagram consists of a polygon whose successive sides represent /\p9
A system of forces represented completely by the sides of I plane polygon taken in order is equivalent to a couple whosc moment is represented by twice the area of the polygon; this is proved by taking moments about any point.
If the polygon intersects itself, care must be taken to attribute to the different parts of the area their proper signs.
The sides of the force-polygon may in the first instance be arranged in any order; the force-diagram can then be completed in a doubly infinite number of ways, owing to the arbitrary position of 0; and for each force-diagram a simply infinite number of funiculars can be drawn.
When the given forces are all parallel, the force-polygon consists of a series of segments of a straight line.
Hence if a system of vertical forces be in equilibrium, so that the funicular polygon ii closed, the length which this polygon intercepts on the vertical through any point P gives the sum of the moments about P of all the forces on one side of this vertical.
This may be called a partial polygon of resistances.
A curve tangential to all the sides of the polygon is the line of pressures.
For figures of more than four sides this method is not usually convenient, except for such special cases as that of a regular polygon, which can be divided into triangles C by radii drawn from its centre.
This result is easily extended to the case of a polygon of any number of sides; it has an important application in hydrostatics.
As a special case it may happen that the force-polygon is closed, i.e.
Thus ii AB, BC, CD represent the given loads, in the force-diagram, we construct the sides corresponding to OA, OB, OC, OD in the funicular; we then draw the closing line of the funicular polygon, and a parallel OE to it in the force diagram.
P4 represent the centres of load in a structure of four pieces, and the sides of the ~ polygon of resistances P1 P2 P2 P4 represent respectively the direc~ I~~ tions and positions FIG.
When the load on one of the pieces is parallel to the resistances which balance it, the polygon of resistances ceases to be closed, two of the sides becoming parallel to each other and to the load in question, and extending indefinitely.
Partial Polygons of Resistance.In a structure in which there are pieces supported at more than two joints, let a polygon be con-.
Line of PressuresCentres and Line of Resistance.The line of pressures is a line to which the directions of all the resistances in one polygon are tangents.
67 d as the complete reciprocal figure of the frame and forces upon it, and we see that each line in the reciprocal figure measures the stress on the corresponding member in the frame, and that the polygon of forces acting at any point, as Ijky, in the frame is represented by a polygon of the same name in the reciprocal figure.
This is equivalent to imagining the polygon Jii Jar J14..., supposed fixed in the l~mina, to roll on the polygon J12 Jar which is supposed fixed in space.