## Oz Sentence Examples

- "Now," said the Wizard of
**Oz**, "having created something from nothing, I will make something nothing again." - Our friend
**Oz**is merely a humbug wizard, for he once proved it to me. - "The girl that rules the marvelous Land of
**Oz**," was the reply. - Queensland's annual output is between 750,000 and 800,000
**oz**.; the number of men engaged in goldmining is io,000. - In New South Wales the greatest production was in 1852, soon after the first discovery of the precious metal, when the output was valued at £2,660,946; the production in 1905 was about 270,000
**oz**., valued at £1,150,000. - In 1905 the production amounted to 1,983,000
**oz**., valued at £8,300,000. - The electromotive force of each cell is i 07 volts and the resistance 3 ohms. The Fuller bichromate battery consists of an outer jar containing a solution of bichromate of potash and sulphuric acid, in which a plate of hard carbon is immersed; in the jar there is also a porous pot containing dilute sulphuric acid and a small quantity (2
**oz**.) of mercury, in which stands a stout zinc rod. - For the first
**oz**., and i3/4d. - The internal rate is 15c. (i3/4d.) per 3/4
**oz**.; post-cards foe. - Gold-mining and quartz-mining are its principal industries, and in 1907 Nevada county's output of gold (104,J90.76
**oz**., worth $2,162,083) was second only to that of Butte county (134,813.39**oz**., worth $2,786,840) in California; the county is the leading producer 1 Died the 21st of September, 1890, and Frank Bell became governor by virtue of his office as lieutenant-governor. - In West Siberia, however, quartz-mining is steadily increasing in importance: whereas in 1900 the output of gold from this source was less than 10,000
**oz**., in 1904 it amounted, to close upon 50,000**oz**. - On the other hand gravel-washing gives a declining yield in West Siberia, for while in 1900 the output from this source was approximately 172,000
**oz**., in 1904 it was only 81,000**oz**. - The total yield annually amounts to some 700,000
**oz**., the largest quantity coming from the Olekminsk, district in the province of Yakutsk, and this district is followed by the Amur region, the Maritime province, and Nerchinsk and Transbaikalia. - -, reduce s x2ax1 -x10x2 to the form j
**Oz**ON 2 1 1 j 2 i The Binary Quintic.-The complete system consists of 23 forms, of which the simplest are f =a:; the Hessian H = (f, f') 2 = (ab) 2axbz; the quadratic covariant i= (f, f) 4 = (ab) 4axbx; and the nonic co variant T = (f, (f', f") 2) 1 = (f, H) 1 = (aH) azHi = (ab) 2 (ca) axbycy; the remaining 19 are expressible as transvectants of compounds of these four. - The force operative upon the positive half is parallel to
**OZ**, and of amount per unit of area equal to - b 2 D = b 2 kD cos nt; and to this force acting over the whole of the plane the actual motion on the positive side may be conceived to be due. - According to (18), the effect of the force acting at dS parallel to
**OZ**, and of amount equal to 2b2kD dS cos nt, will be a disturbance - dS sin cos (nt - kr) (20), regard being had to (12). - Deep. The yield of the Rand mines, in 1887 but 23,000
**oz**., rose in 1888 to 208,000**oz**. - In 1892 the yield was 1,210,000
**oz**.: in 1896 it exceeded 2,280,000**oz**. - In 1905 when a full supply of labour was again available the output was 4,760,000
**oz**., in which year the sum distributed in dividends to shareholders in the Rand mines was over £4,800,000. - Though several large nuggets have been found (the largest weighing 215
**oz**.), the total production is not great, the highest output obtained by washing being worth about £300,000 in one year. - Work was begun in 1895, and the yield of gold in that year was 274
**oz**., which increased to 893**oz**. - As an example of the general equations, take the simplest case of a uniform field of gravity, with
**Oz**directed vertically downward; employing the gravitation unit of force, 1 dp i dp t dp dp/dz = p = pzn (4) z n+I pz 1 /n p-p n-H ?t), (5) supposing p and p to vanish together. - If homogeneous liquid is drawn off from a vessel so large that the motion at the free surface at a distance may be neglected, then Bernoulli's equation may be written H = PIP--z - F4 2 / 2g = P/ p +h, (8) where P denotes the atmospheric pressure and h the height of the free surface, a fundamental equation in hydraulics; a return has been made here to the gravitation unit of hydrostatics, and
**Oz**is taken vertically upward. - (7) Interchanging these values =m log r, 4, = mO, 4,+4,i =m log rei e (8) gives a state of vortex motion, circulating round
**Oz**, called a straight or columnar vortex. - In plane motion the kinetic energy per unit length parallel to
**Oz**T 2p J J [(d4)) 2+ (d dy (P)1dxdy=lpfl[ a) 2+ (=zp 4d ds=zp f, ydvds. - For in a rigid body, rotating about
**Oz**with angular velocity the circulation round a curve in the plane xy is x ds yds) ds = times twice the area. - This is so when the axis of revolution is a principal axis, say
**Oz**; when S21=0, t 2 =0, =o, o=0. - Similarly, the inertia parallel to Oy and
**Oz**is NW' - 1 B W', B C (b2 +-X, c 2 ab and A +C abc/ZP, Ao For a sphere a=b=c, Ao= Bo=Co =, 'a' = Q = = z, (9) U from (II), (16) so that the effective inertia of a sphere is increased by half the weight of liquid displaced; and in frictionless air or liquid the sphere, of weight W, will describe a parabola with vertical acceleration W - W', g (30) W+ aW Thus a spherical air bubble, in which W/W' is insensible, will begin to rise in water with acceleration 2g. - Clebsch, by taking a velocity function 4,=xyx (I) for a rotation R about
**Oz**; and a similar procedure shows that an ellipsoidal surface A may be in rotation about**Oz**without disturbing the motion if I I dx + _ a2'-A) x 2 a R t i/(b2+A)- i/(a2+A) and that the continuity of the liquid is secured if (a 2 _ I -A) 3/2 (b 2 4 A)3f2(C2 -+- A) 2 ?? - These equations are proved by taking a line fixed in space, whose direction cosines are 1, then dt=mR-nQ,' d'-t = nP =lQ-mP. (5) If P denotes the resultant linear impulse or momentum in this direction P =lxl+mx2+nx3, ' dP dt xl+, d y t x2' x3 +1 dtl dt 2 +n dt3, =1 ('+m (dt2-x3P+x1R) ' +n ('-x1Q-{-x2P) ' '= IX +mY+nZ, / (7) for all values of 1, Next, taking a fixed origin and axes parallel to Ox, Oy,
**Oz**through 0, and denoting by x, y, z the coordinates of 0, and by G the component angular momentum about 1"2 in the direction (1, G =1(yi-x2z+x3y) m 2-+xlz) n(y(y 3x 1 x3x y + x 2 x) (8) Differentiating with respect to t, and afterwards moving the fixed. - The largest amount of alcohol that can be burnt up within the healthy body in twenty-four hours is 12
**oz**., but it must be consumed in great dilution and divided into small doses taken every four hours. - Again, the components of angular momentum about OC, OA are Cn,A sin 0~, and therefore the angular momentum (u, say) about
**OZ**is pA sini 0 ~+Cn cosU. - 83
**OZ**is supposed to be vertical, and OC is the axis of the solid drawn in the direction 0G. - In the case of the top, the equation of energy and the condition of constant angular momentum (~l) about the vertical
**OZ**are sufficient to determine the motion of the axis. - Now consider a system of fixed axes Ox, Oy,
**Oz**chosen so as to coincide at the instant I with the moving system Ox, Oy, Os. - If we now apply them to the case of a rigid body moving about a fixed point 0, and make Ox, Oy,
**Oz**coincide with the principal axes of inertia at 0, we have X, u, v=Ap, Bq, Cr, whence A (B C) qr = L, - J To prove these, we may take fixed axes Ox, Oy,
**Oz**coincident with the moving axes at time t, and compare the linear and angular momenta E+E, ~ ~ ?~+~X, u+u, v+~v relative to the new position of the axes, Ox, Oy,**Oz**at time t+t with the original momenta ~, ~ ~, A, j~i, v relative to Ox, Oy,**Oz**at time t. - Let r be the distance of a point P from a fixed origin 0, 0 the angle which OP makes with a fixed direction
**OZ**, il the azimuth of the plane ZOP relative to some fixed plane through**OZ**. - In the case of the spherical pendulum we have r=l, e= mgi sin 0, s=o, if
**OZ**be drawn vertically downwards, and therefore sin 0 cos Ol1 ~ sin 0, ~- (23) - The latter equation expresses that the angular momentum mP sing O~t about the vertical
**OZ**is constant. - The meaning of these quantities is easily recognized; thus X is the angular momentum about a horizontal axis normal to the plane of 0, u is the angular momentum about the vertical
**OZ**, and s is the angular momentum about the axis of symmetry.. - 36, if OA, OB, OC be three mutually perpendicular lines in the solid, we may denote by O the angle which OC makes with a fixed direction
**OZ**, by ~ the azimuth of the plane ZOC measured from some fixed plane through**OZ**, and by f~ the inclination of the plane COA to the plane ZOC In fig.