The process of transvection is connected with the operations 12; for?k (a m b n) = (ab)kam-**kbn-k**, (x y x y or S 2 k (a x by) x = 4))k; so also is the polar process, for since f k m-k k k n - k k y = a x by, 4)y = bx by, if we take the k th transvectant of f i x; over 4 k, regarding y,, y 2 as the variables, (f k, 4)y) k (ab) ka x -**kb** k (f, 15)k; or the k th transvectant of the k th polars, in regard to y, is equal to the kth transvectant of the forms. Moreover, the kth transvectant (ab) k a m-k b: -k is derivable from the kth polar of ax, viz.

Du Bois believes this to be an important general law, applicable to the case of every paramagnetic substance, and suggests that the product **KB** should be known as " Curie's constant " for the substance.

Then, if we take ordinates **Kb**, Lg, Mc, Nd, Pf, equal to B'B, GG', C'C, D'D, FF', the figure abgcdfe will be the equivalent trapezoid, and any ordinate drawn from the base to the a LM N P e X top of this trapezoid will be equal to the portion of this ordinate (produced) which falls within the original figure.

+ [(-) **kb** k h2k d x 2k l 1)k+lbk+1h2k+2 + J x = xo, where P, Q, R,.

**Kb**(30s, a cube), in geometry, a solid bounded by six equal squares, so placed that the angle between any pair of adjacent faces is a right angle.

Cardwell in his edition of the Nicomachean Ethics (1828) had the wisdom to found his text on the Laurentian Manuscript (**Kb**); E.

From El **Kb** southward its place was taken by Libyan sandstone, soft and easily worked, but unsuitable for fine sculpture.

(**KB**), seems as near the autograph as that of any other part of the New Testament; whereas the " Western " text, even in its earliest traceable forms, is secondary.

Then tb represents the angular acceleration of the point B relatively to the point K and hence tb/**KB** is the value of A, the angular acceleration of the link.

L3ennett3 which is as follows: Let OK be the crank and **KB** the connecting rod.

Then tb represents the angular acceleration of the point B relatively to the point K and hence tb/**KB** is the value of A, the angular acceleration of the link.

L3ennett3 which is as follows: Let OK be the crank and **KB** the connecting rod.