## Cot Sentence Examples

- Since the plates are very near one another we may use the following equation of the surface as an approximation: y= h1+Ax+Bx 2, h2=h1+Aa+Ba2, whence
**cot**a 1 = - A,**cot**a 2 =A+2Ba T(cos a i +cos a 2) = +3Ba2), whence we obtain h, = g (cos a, +cos a 2) +6 (2**cot**a, -**cot**a2) h 2 = - T (cos a,+cos a 2) +6**cot**a2 -**cot**al) Let X be the force which must be applied in a horizontal direction to either plate to keep it from approaching the other, then the forces acting on the first plate are T+X in the negative direction, and T sin a t + 2gph 1 2 in the positive direction. - There were in the room a child's
**cot**, two boxes, two armchairs, a table, a child's table, and the little chair on which Prince Andrew was sitting. - A comfortable bed replaced the
**cot**utilized in Peabody and absolute darkness proved more conducive to sleep than the leaked light that often snuck into our old quarters. - Whence
**cot**0 = a + b. - V = 3rA = 2 1 4 / 3 n F tan -II
**cot**e a = 2 I 1 3 n F**cot**e a cos a/ (sin' a -cos t 13) 2 R =1-/ tan IT tan 0=1/ sin 13/(sin e a-cost r =Zl tan 21**cot**a= Il**cot**a cos 13/(sin" a -cos' (3)L 1 In the language of Proclus, the commentator: " The equilateral triangle is the proximate cause of the three elements, ` fire,' ` air ' and ` water '; but the square is annexed to the ` earth.' - In order to adapt this formula to logarithms, we introduce a subsidiary angle p, such that
**cot**p =**cot**l cos t; we then have cos D = sin 1 cos( - p) I sin p. In the above formulae our earth is assumed to be a sphere, but when calculating and reducing to the sea-level, a base-line, or the side of a primary triangulation, account must be taken of the spheroidal shape of the earth and of the elevation above the sealevel. - Exact formulae are: - Area = 2a 2 (0 - sin 0)=1a 2 0 - 4c2
**cot**zB =Za 2 -2 c?1 (a 2 -4c 2). - Equating this to the rate of increase of the angular momentum about OB, investigated as above, we find (C+Ma2+A~ cos e)~~=Mg ~-
**cot**0, (4) - A =1 l 2 nF
**cot**a. - Solving for
**cot**e i we obtain 2**cot**2 i= (p 2 -1) 2 {(p2 - tan2 (7r - A)/4) {p - cot2 - A)/411, and since tan { (ir - A)/4-} is less than unity, p must exceed**cot**{Or - A)/41 if**cot**2 i is to be real. - Dip. et
**Cot**., February I6, 1905). - Bands of desperadoes Ri(re formed, commanded by the most infamous criminals and by h~s cigners who came to fight in what they were led to believe was 1 Italian Vende, but which was in reality a c~impaign of butchery
**cot**1 plunder. - His memory is appropriately kept green by a
**cot**in the Children's Hospital, Great Ormond Street, London, which was endowed perpetually by a public subscription. - Long to move through ro in., so that GM (2) also
**cot**0 = 24, 8 =2° 2 4 '. - (iv) To find the volume of a prismoidal cutting with vertical ends, and with sides equally inclined to the vertical, so that 4 =0, let the value t of h, for the two ends be h, ?, and h2, 1k21 and write ml_ do 0 (a + h 1
**cot**0), o 0 (a + hi**cot**0), ot + h2**cot**0), n2 - o +**cot**B (a + h2**cot**0). **Cot**Then volume of prismoid = length X If mini + m2n2 + 2 (m i ne + m270-3a 2 1 tan 0.- We put and call C the ballistic coefficient (driving power) of the shot, so that (6) At =
**COT**, where (7) AT = Av/gp, and AT is the time in seconds for the velocity to drop Av of the standard shot for which C = I, and for which the ballistic table is calculated. - - N / (z
**cot**IC) =o, with centre sin A, sin B, sin C; the escribed circle opposite the angle A is - N I (- x**cot**ZA)+ -1 (y tan 2B) + -V (z tan 2C) =o, with centre - sin A, sin B, sin C; and the selfconjugate circle is x 2**cot**A+y 2**cot**B+z 2**cot**C =o, with centre tan A, tan B, tan C. Since in areal co-ordinates the line infinity is represented by the equation x+y+z=o it is seen that every circle is of the form a 2 yz+b 2 zx+c 2 xy+(lx+my+nz)(x+y+z) = o. - Comparing this equation with ux 2 +vy 2 +w2 2 +22G'y2+2v'zx+2W'xy=0, we obtain as the condition for the general equation of the second degree to represent a circle :- (v+w-2u')Ia 2 = (w +u -2v')/b2 = (u+v-2w')lc2 In tangential q, r) co-ordinates the inscribed circle has for its equation(s - a)qr+ (s - b)rp+ (s - c) pq = o, s being equal to 1(a +b +c); an alternative form is qr
**cot**zA+rp**cot**ZB +pq cot2C =o; Tangential the centre is ap+bq+cr = o, or sinA +q sin B+rsinC =o. - +(s - b)pq= oor - qr
**cot**2A+rptan ZB +pgtan 2C=o,with centre - ap+bq+cr = o. - A
**cot**a b**cot**$ - Substituting this, we find
**cot**y = U-y, whence 5 7 y U(1+/-1-2:-+2...) - y3 -15-315' This equation is to be solved by successive approximation. - If the ship heels through an angle 0 or a slope of I in m, GM =GG 1
**cot**8=mc(P/W), (r) and GM is called the metacentric height; and the ship must be ballasted, so that G lies below M. - Of raw
**cotton**imported, exported and retained for**Cot**consumption for various years during the period1890-1910were as follows: During the same period the minimum and maximum amount of raw**cotton**(in lb) imported into the United Kingdom from the principal countries whence it is exported was as follows: United States of America (1893), 1, 0 55, 8 55,3 60; (1898), 1,805,353,424; Egypt (1890), 181,266,176; (1907), 4 2 3, 0 5 2, 44 8; British possessions in the East Indies (1898), 27,349,728; (1890), 2 3 8, 74 6, 7 0 4; (1909), 75,621,168;75,621,168; Brazil (1899), 5,4 6 4,59 2; (1906), 54,362,000; Peru (1891), 6, 1 75,344; (1909), 2 4,4 1 3,§4 8.8. - (iii) If = o, so that AD is parallel to BC, it becomes area = 2ah+ 2 (
**cot****cot**ct,)h2. - Af d4e tan ~,+
**cot**4i~ ~ (40) aj d~i tan ~1+**cot**ti)